HMMT 二月 2007 · TEAM1 赛 · 第 5 题
HMMT February 2007 — TEAM1 Round — Problem 5
题目详情
英文原题
- [ 30 ] Prove the identity
∑ ∑2
3
τ ( d ) = τ ( d ) .
d | n d | n
解析
英文解析
- [ 30 ] Prove the identity
∑ ∑2
3
τ ( d ) = τ ( d ) .
d | n d | n
Solution. Note that τ is multiplicative; in light of the convolution property just shown, it follows 3
that both sides of the posed equality are multiplicative. Thus, it would suffice to prove the claim forkn a power of a prime. So, write n = p where p is a prime and k is a nonnegative integer. Thenk k
∑ ∑ ∑
( )
3 i 33
τ ( d ) = τ p = ( i + 1)
i =0 i =0
d | n
( )
2 22
( k + 1) ( k + 2) ( k + 1)( k + 2)
3 3 = 1 + · · · + ( k + 1) = =
4 2
( )2
k 2
∑ ∑
( )
i = τ p = τ ( d ) ,
i =0
d | nas required. 2