HMMT 二月 2007 · 冲刺赛 · 第 3 题
HMMT February 2007 — Guts Round — Problem 3
题目详情
- [ 5 ] The equation x + 2 x = i has two complex solutions. Determine the product of their real parts.
10 HARVARD-MIT MATHEMATICS TOURNAMENT, 24 FEBRUARY 2007 — GUTS ROUNDth
英文原题
[ 5 ] The equation x 2 + 2 x = i has two complex solutions. Determine the product of their real parts.
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10 th HARVARD-MIT MATHEMATICS TOURNAMENT, 24 FEBRUARY 2007 — GUTS ROUND
解析
英文解析
- [ 5 ] The equation x + 2 x = i has two complex solutions. Determine the product of their real parts.
√
√
1 − 2 2 iπ
Answer: . Complete the square by adding 1 to each side. Then ( x + 1) = 1 + i = e 2, so 4
√2
4 iπx + 1 = ± e 2. The desired product is then 8
( ( ))
√
( ( ) ) ( ( ) ) ( )π
√ √ √ √
1 + cosπ π π 1 − 2
4 4
2 4 − 1 + cos 2 − 1 − cos 2 = 1 − cos 2 = 1 − 2 = .
8 8 8 2 2
10 HARVARD-MIT MATHEMATICS TOURNAMENT, 24 FEBRUARY 2007 — GUTS ROUNDth