返回题库

HMMT 二月 2007 · GEN2 赛 · 第 8 题

HMMT February 2007 — GEN2 Round — Problem 8

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 5 ] Compute the number of sequences of numbers a , a , . . . , a such that
    1 2 10
    I. a = 0 or 1 for all ii
    II. a · a = 0 for i = 1 , 2 , . . . , 9
    i i +1
    III. a · a = 0 for i = 1 , 2 , . . . , 8 .
    i i +2
解析

英文解析

  1. [ 5 ] Compute the number of sequences of numbers a , a , . . . , a such that
    1 2 10
    I. a = 0 or 1 for all ii
    II. a · a = 0 for i = 1 , 2 , . . . , 9
    i i +1
    III. a · a = 0 for i = 1 , 2 , . . . , 8 .
    i i +2
    Answer: 60 . Call such a sequence “good,” and let A be the number of good sequences of lengthnn . Let a , a , . . . , a be a good sequence. If a = 0, then a , a , . . . , a is a good sequence if and only
    1 2 n 1 1 2 nif a , . . . , a is a good sequence, so there are A of them. If a = 1, then we must have a = a = 0,
    2 n n − 1 1 2 3
    and in this case, a , a , . . . , a is a good sequence if and only if a , a , . . . , a is a good sequence,
    1 2 n 4 5 nso there are A of them. We thus obtain the recursive relation A = A + A . Note thatn − 3 n n − 1 n − 3
    A = 2 , A = 3 , A = 4 . Plugging these into the recursion eventually yields A = 60 .
    1 2 3 10