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HMMT 二月 2007 · GEN2 赛 · 第 5 题

HMMT February 2007 — GEN2 Round — Problem 5

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 4 ] A best of 9 series is to be played between two teams. That is, the first team to win 5 games is thewinner. One of the teams, the Mathletes, has a 2/3 chance of winning any given game. What is the probability that the winner is determined in the 7 th game?
解析

英文解析

  1. [ 4 ] A best of 9 series is to be played between two teams. That is, the first team to win 5 games is thewinner. One of the teams, the Mathletes, has a 2/3 chance of winning any given game. What is the probability that the winner is determined in the 7 th game?
    Answer: . If the Mathletes are the winners, they must win the 7 th game and have won exactly 20
    four of the previous 6 games. The probability of this occurring is 81
    ( ( ))
    4 26
    (2 / 3) · (1 / 3) · · (2 / 3) .
    ( )2
    ( )
    4 2
    Analogously, the other team wins with probability (1 / 3) · (2 / 3) · · (1 / 3). Summing, the prob-6
    ability is 2
    ( ) ( )
    2 3 2 56
    · 2 · 2 · 1 + 1
    5 · 4 20 = = .2
    7 4
    3 3 81