HMMT 二月 2007 · GEN2 赛 · 第 5 题
HMMT February 2007 — GEN2 Round — Problem 5
题目详情
英文原题
- [ 4 ] A best of 9 series is to be played between two teams. That is, the first team to win 5 games is thewinner. One of the teams, the Mathletes, has a 2/3 chance of winning any given game. What is the probability that the winner is determined in the 7 th game?
解析
英文解析
- [ 4 ] A best of 9 series is to be played between two teams. That is, the first team to win 5 games is thewinner. One of the teams, the Mathletes, has a 2/3 chance of winning any given game. What is the probability that the winner is determined in the 7 th game?
Answer: . If the Mathletes are the winners, they must win the 7 th game and have won exactly 20
four of the previous 6 games. The probability of this occurring is 81
( ( ))
4 26
(2 / 3) · (1 / 3) · · (2 / 3) .
( )2
( )
4 2
Analogously, the other team wins with probability (1 / 3) · (2 / 3) · · (1 / 3). Summing, the prob-6
ability is 2
( ) ( )
2 3 2 56
· 2 · 2 · 1 + 1
5 · 4 20 = = .2
7 4
3 3 81