HMMT 二月 2007 · CALC 赛 · 第 2 题
HMMT February 2007 — CALC Round — Problem 2
题目详情
- [ 3 ] Determine the real number a having the property that f ( a ) = a is a relative minimum of f ( x ) = 4 3 2 x − x − x + ax + 1.
解析
- [ 3 ] Determine the real number a having the property that f ( a ) = a is a relative minimum of f ( x ) = 4 3 2 x − x − x + ax + 1. ′ 3 2 Answer: 1 . Being a relative minimum, we have 0 = f ( a ) = 4 a − 3 a − 2 a + a = a (4 a + 1)( a − 1). Then a = 0 , 1 , − 1 / 4 are the only possibilities. However, it is easily seen that a = 1 is the only value satisfying f ( a ) = a .