HMMT 二月 2006 · TEAM2 赛 · 第 12 题
HMMT February 2006 — TEAM2 Round — Problem 12
题目详情
- [15] Find all ordered triples ( x, y, z ) of positive reals such that x + y + z = 27 and x + y + z − xy − yz − zx = 0. Prove that your answer is correct.
解析
- [15] Find all ordered triples ( x, y, z ) of positive reals such that x + y + z = 27 and 2 2 2 x + y + z − xy − yz − zx = 0. Prove that your answer is correct. Answer: (9 , 9 , 9) 2 2 2 ( x − y ) + ( y − z ) + ( z − x ) 2 2 2 Solution: We have x + y + z − xy − yz − zx = = 0, 2 27 which implies x = y = z = = 9. 3