HMMT 二月 2006 · 冲刺赛 · 第 39 题
HMMT February 2006 — Guts Round — Problem 39
题目详情
英文原题
- [15] A fat coin is one which, when tossed, has a 2 / 5 probability of being heads, 2 / 5 of beingtails, and 1 / 5 of landing on its edge. Mr. Fat starts at 0 on the real line. Every minute, hetosses a fat coin. If it’s heads, he moves left, decreasing his coordinate by 1; if it’s tails, hemoves right, increasing his coordinate by 1. If the coin lands on its edge, he moves back to
- If Mr. Fat does this ad infinitum , what fraction of his time will he spend at 0?
IX HARVARD-MIT MATHEMATICS TOURNAMENT, 25 FEBRUARY 2006 — GUTS ROUNDth
∞
∑
3 k + 1
k +1
解析
英文解析
- A fat coin is one which, when tossed, has a 2 / 5 probability of being heads, 2 / 5 ofbeing tails, and 1 / 5 of landing on its edge. Mr. Fat starts at 0 on the real line. Everyminute, he tosses a fat coin. If it’s heads, he moves left, decreasing his coordinate by
1; if it’s tails, he moves right, increasing his coordinate by 1. If the coin lands on itsedge, he moves back to 0. If Mr. Fat does this ad infinitum , what fraction of his timewill he spend at 0?
Answer:1
Solution: For n ∈ Z , let a be the fraction of the time Mr. Fat spends at n . By 3
symmetry, a = a for all n .nn − n
2 2 5
For n > 0, we have a = a + a , or a = a − a . This Fibonacci-liken n − 1 n +1 n +1 n n − 1
5 5 2
recurrence can be solved explicitly to obtain
| n | −| n |
a = α · 2 + β · 2
for all n ∈ Z . Now we also haven
∑
a = 1 ,
n ∈ Znβso we better have α = 0, so that a = β and a = . Now we also have a =
0 ± 1 0
∑2
2 2 1 1
a + a + , so β = . This matches perfectly with a = 1 .
− 1 1 nn ∈ Z
5 5 5 3