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HMMT 二月 2006 · 冲刺赛 · 第 39 题

HMMT February 2006 — Guts Round — Problem 39

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [15] A fat coin is one which, when tossed, has a 2 / 5 probability of being heads, 2 / 5 of beingtails, and 1 / 5 of landing on its edge. Mr. Fat starts at 0 on the real line. Every minute, hetosses a fat coin. If it’s heads, he moves left, decreasing his coordinate by 1; if it’s tails, hemoves right, increasing his coordinate by 1. If the coin lands on its edge, he moves back to
  2. If Mr. Fat does this ad infinitum , what fraction of his time will he spend at 0?
    IX HARVARD-MIT MATHEMATICS TOURNAMENT, 25 FEBRUARY 2006 — GUTS ROUNDth
    ∞
    ∑
    3 k + 1
    k +1
解析

英文解析

  1. A fat coin is one which, when tossed, has a 2 / 5 probability of being heads, 2 / 5 ofbeing tails, and 1 / 5 of landing on its edge. Mr. Fat starts at 0 on the real line. Everyminute, he tosses a fat coin. If it’s heads, he moves left, decreasing his coordinate by
    1; if it’s tails, he moves right, increasing his coordinate by 1. If the coin lands on itsedge, he moves back to 0. If Mr. Fat does this ad infinitum , what fraction of his timewill he spend at 0?
    Answer:1
    Solution: For n ∈ Z , let a be the fraction of the time Mr. Fat spends at n . By 3
    symmetry, a = a for all n .nn − n
    2 2 5
    For n > 0, we have a = a + a , or a = a − a . This Fibonacci-liken n − 1 n +1 n +1 n n − 1
    5 5 2
    recurrence can be solved explicitly to obtain
    | n | −| n |
    a = α · 2 + β · 2
    for all n ∈ Z . Now we also haven
    ∑
    a = 1 ,
    n ∈ Znβso we better have α = 0, so that a = β and a = . Now we also have a =
    0 ± 1 0
    ∑2
    2 2 1 1
    a + a + , so β = . This matches perfectly with a = 1 .
    − 1 1 nn ∈ Z
    5 5 5 3