HMMT 二月 2006 · 冲刺赛 · 第 3 题
HMMT February 2006 — Guts Round — Problem 3
题目详情
- [5] At a nursey, 2006 babies sit in a circle. Suddenly each baby pokes the baby immediatelyto either its left or its right, with equal probability. What is the expected number of unpokedbabies?
IX HARVARD-MIT MATHEMATICS TOURNAMENT, 25 FEBRUARY 2006 — GUTS ROUNDth
英文原题
[5] At a nursey, 2006 babies sit in a circle. Suddenly each baby pokes the baby immediately
to either its left or its right, with equal probability. What is the expected number of unpoked
babies?
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
IX th HARVARD-MIT MATHEMATICS TOURNAMENT, 25 FEBRUARY 2006 — GUTS ROUND
解析
英文解析
- At a nursey, 2006 babies sit in a circle. Suddenly each baby pokes the baby immediatelyto either its left or its right, with equal probability. What is the expected number ofunpoked babies?
1003
Answer:
Solution: The probability that any given baby goes unpoked is 1 / 4. So the answer 2
is 2006 / 4 = 1003 / 2.