HMMT 二月 2005 · TEAM1 赛 · 第 1 题
HMMT February 2005 — TEAM1 Round — Problem 1
题目详情
英文原题
- [15] Prove that for any two types of dominoes, there exists a rectangle that can betiled by dominoes of either type.
解析
英文解析
- [15] Prove that for any two types of dominoes, there exists a rectangle that can betiled by dominoes of either type.
Solution: Note that a type ( a, b ) domino tiles a max { 1 , 2 a }× 2 b rectangle (see diagram
′ ′
for a > 0). Then both type ( a, b ) and type ( a , b ) dominoes tile a (max { 1 , 2 a } ·
′ ′
max { 1 , 2 a } ) × (2 b · 2 b ) rectangle.
b ba a