HMMT 二月 2005 · 冲刺赛 · 第 21 题
HMMT February 2005 — Guts Round — Problem 21
题目详情
- [8] In triangle ABC with altitude AD , ∠ BAC = 45 , DB = 3, and CD = 2. Find the area of triangle ABC .
HARVARD-MIT MATHEMATICS TOURNAMENT, FEBRUARY 19, 2005 — GUTS ROUND
英文原题
[8] In triangle ABC with altitude AD , ∠ BAC = 45 ◦ , DB = 3, and CD = 2. Find the
area of triangle ABC .
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HARVARD-MIT MATHEMATICS TOURNAMENT, FEBRUARY 19, 2005 — GUTS ROUND
解析
英文解析
- In triangle ABC with altitude AD , ∠ BAC = 45 , DB = 3, and CD = 2. Find the area of triangle ABC .
Solution: 15
Suppose first that D lies between B and C . Let ABC be inscribed in circle ω , andextend AD to intersect ω again at E . Note that A subtends a quarter of the circle, soin particular, the chord through C perpendicular to BC and parallel to AD has length
BC = 5. Therefore, AD = 5 + DE . By power of a point, 6 = BD · DC = AD · DE =
2 1
AD − 5 AD , implying AD = 6, so the area of ABC is BC · AD = 15.
√2
If D does not lie between B and C , then BC = 1, so A lies on a circle of radius 2 / 2
through B and C . But then it is easy to check that the perpendicular to BC through
D cannot intersect the circle, a contradiction.
B7
CDAE