HMMT 二月 2005 · CALC 赛 · 第 9 题
HMMT February 2005 — CALC Round — Problem 9
题目详情
- Compute ∞ ∑ 4 . (4 k )! k =0 ′
解析
- Compute ∞ ∑ 4 . (4 k )! k =0 Solution: e + 1 /e + 2 cos 1 3 This is the power series 4 8 4 x 4 x 4 + + + · · · 4! 8! evaluated at x = 1. But this power series can be written as the sum ( ) 2 3 4 5 6 7 x x x x x x x 1 + + + + + + + + · · · 1! 2! 3! 4! 5! 6! 7! ( ) 2 3 4 5 6 7 x x x x x x x
- 1 − + − + − + − + · · · 1! 2! 3! 4! 5! 6! 7! ( ) 2 4 6 x x x
- 2 1 − + − + · · · 2! 4! 6! x − x = e + e + 2 cos x. It follows that the quantity is e + 1 /e + 2 cos 1. ′