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HMMT 二月 2005 · 代数 · 第 7 题

HMMT February 2005 — Algebra — Problem 7

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. Let x be a positive real number. Find the maximum possible value of

    x + 2 − x + 442
    . x
解析

英文解析

  1. Let x be a positive real number. Find the maximum possible value of

    x + 2 − x + 442
    .
    2 x

    Solution: 2 2 − 2
    Rationalizing the numerator, we get
    √ √
    2 2 2 2 4
    4 4
    x + 2 − x + 4 x + 2 + x + 4 ( x + 2) − ( x + 4)
    · √ = √
    2 4 2 4
    x + 2 + x + 4 x ( x + 2 + x + 4)x
    4 x 2

    2 4=
    x ( x + 2 + x + 4)
    √4
    1=
    2 4
    ( x + 2 + x + 4)
    4 x

    = .
    2 4
    x + + x +2
    x x 2
    Since we wish to maximize this quantity, we wish to minimize the denominator. By
    √ √
    2 4
    AM-GM, x + ≥ 2 2 and x + ≥ 4, so that the denominator is at least 2 2 + 2.2
    x x 2
    Therefore,

    √42
    x + 2 − x + 4 4

    ≤ = 2 2 − 2 ,
    2 2 + 2 x

    with equality when x = 2.