HMMT 二月 2005 · 代数 · 第 7 题
HMMT February 2005 — Algebra — Problem 7
题目详情
英文原题
- Let x be a positive real number. Find the maximum possible value of
√
x + 2 − x + 442
. x
解析
英文解析
- Let x be a positive real number. Find the maximum possible value of
√
x + 2 − x + 442
.
2 x
√
Solution: 2 2 − 2
Rationalizing the numerator, we get
√ √
2 2 2 2 4
4 4
x + 2 − x + 4 x + 2 + x + 4 ( x + 2) − ( x + 4)
· √ = √
2 4 2 4
x + 2 + x + 4 x ( x + 2 + x + 4)x
4 x 2
√
2 4=
x ( x + 2 + x + 4)
√4
1=
2 4
( x + 2 + x + 4)
4 x
√
= .
2 4
x + + x +2
x x 2
Since we wish to maximize this quantity, we wish to minimize the denominator. By
√ √
2 4
AM-GM, x + ≥ 2 2 and x + ≥ 4, so that the denominator is at least 2 2 + 2.2
x x 2
Therefore,
√
√42
x + 2 − x + 4 4
√
≤ = 2 2 − 2 ,
2 2 + 2 x
√
with equality when x = 2.