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HMMT 二月 2004 · 冲刺赛 · 第 19 题

HMMT February 2004 — Guts Round — Problem 19

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [8] The Fibonacci numbers are defined by F = F = 1, and F = F + F for
    1 2 n n − 1 n − 2
    n ≥ 3. If the number
    F F
    2003 2004
    F F−
    2002 2003
    is written as a fraction in lowest terms, what is the numerator?
解析

英文解析

  1. The Fibonacci numbers are defined by F = F = 1, and F = F + F for n ≥ 3.
    1 2 n n − 1 n − 2
    If the number
    F F
    2003 2004
    F F−
    2002 2003
    is written as a fraction in lowest terms, what is the numerator?
    Solution: 1
    2 2
    Before reducing, the numerator is F − F F . We claim F − F F =
    2002 2004 n − 1 n +1
    2003 nn +1
    ( − 1) , which will immediately imply that the answer is 1 (no reducing required).
    This claim is straightforward to prove by induction on n : it holds for n = 2, and if itholds for some n , then
    2 2 n +1 n +2
    F − F F = F ( F + F ) − F ( F + F ) = F F − F = − ( − 1) = ( − 1) .
    n n +2 n +1 n − 1 n n n n +1 n +1 n − 1
    n +1 n