HMMT 二月 2004 · 几何 · 第 1 题
HMMT February 2004 — Geometry — Problem 1
题目详情
英文原题
- In trapezoid ABCD , AD is parallel to BC . A = D = 45 , while B = C = 135 .
If AB = 6 and the area of ABCD is 30, find BC .
B ? C
135 135
45 456
A D
Area = 30
解析
英文解析
- In trapezoid ABCD , AD is parallel to BC . A = D = 45 , while B = C = 135 .
If AB = 6 and the area of ABCD is 30, find BC .
√
Solution: 2 2
Draw altitudes from B and C to AD and label the points of intersection X and Y ,
√
° ° °
respectively. Then ABX and CDY are 45 − 45 − 90 triangles with BX = CY = 3 2.
So, the area of ABX and the area of CDY are each 9, meaning that the area of rectangle
√ √ √
BCY X is 12. Since BX = 3 2, BC = 12 / (3 2) = 2 2.
B 2 2 3 C
3 2 36
9 9
A D
3 2 3 X Y
Area BCYX = 30 − 18 = 12