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HMMT 二月 2004 · 几何 · 第 1 题

HMMT February 2004 — Geometry — Problem 1

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. In trapezoid ABCD , AD is parallel to BC . A = D = 45 , while B = C = 135 .
    If AB = 6 and the area of ABCD is 30, find BC .
    B ? C
    135 135
    45 456
    A D
    Area = 30
解析

英文解析

  1. In trapezoid ABCD , AD is parallel to BC . A = D = 45 , while B = C = 135 .
    If AB = 6 and the area of ABCD is 30, find BC .

    Solution: 2 2
    Draw altitudes from B and C to AD and label the points of intersection X and Y ,

    ° ° °
    respectively. Then ABX and CDY are 45 − 45 − 90 triangles with BX = CY = 3 2.
    So, the area of ABX and the area of CDY are each 9, meaning that the area of rectangle
    √ √ √
    BCY X is 12. Since BX = 3 2, BC = 12 / (3 2) = 2 2.
    B 2 2 3 C
    3 2 36
    9 9
    A D
    3 2 3 X Y
    Area BCYX = 30 − 18 = 12