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HMMT 二月 2004 · GEN1 赛 · 第 10 题

HMMT February 2004 — GEN1 Round — Problem 10

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. A floor is tiled with equilateral triangles of side length 1, as shown. If you drop aneedle of length 2 somewhere on the floor, what is the largest number of triangles itcould end up intersecting? (Only count the triangles whose interiors are met by theneedle — touching along edges or at corners doesn’t qualify.) 2
解析

英文解析

  1. A floor is tiled with equilateral triangles of side length 1, as shown. If you drop aneedle of length 2 somewhere on the floor, what is the largest number of triangles itcould end up intersecting? (Only count the triangles whose interiors are met by theneedle — touching along edges or at corners doesn’t qualify.)
    Solution: 8
    Let L be the union of all the lines of the tiling. Imagine walking from one end of theneedle to the other. We enter a new triangle precisely when we cross one of the linesof the tiling. Therefore, the problem is equivalent to maximizing the number of timesthe needle crosses L . Now, the lines of the tiling each run in one of three directions.
    It is clear that the needle cannot cross more than three lines in any given direction,

    since the lines are a distance 3 / 2 apart and the needle would therefore have to be of

    length greater than 3 3 / 2 > 2. Moreover, it cannot cross three lines in each of twodifferent directions. To see this, notice that its endpoints would have to lie in eitherthe two light-shaded regions or the two dark-shaded regions shown, but the closest twopoints of such opposite regions are at a distance of 2 (twice the length of a side of atriangle), so the needle cannot penetrate both regions.
    Therefore, the needle can cross at most three lines in one direction and two lines ineach of the other two directions, making for a maximum of 3 + 2 + 2 = 7 crossings and
    7 + 1 = 8 triangles intersected. The example shows that 8 is achievable, as long as the

    needle has length greater than 3 < 2. 4