HMMT 二月 2004 · COMB 赛 · 第 6 题
HMMT February 2004 — COMB Round — Problem 6
题目详情
英文原题
- A committee of 5 is to be chosen from a group of 9 people. How many ways can it bechosen, if Bill and Karl must serve together or not at all, and Alice and Jane refuse toserve with each other?
解析
英文解析
- A committee of 5 is to be chosen from a group of 9 people. How many ways can it bechosen, if Bill and Karl must serve together or not at all, and Alice and Jane refuse toserve with each other?
Solution: 41
( )
If Bill and Karl are on the committee, there are = 35 ways for the other group 7
members to be chosen. However, if Alice and Jane are on the committee with Bill and 3
( )
Karl, there are = 5 ways for the last member to be chosen, yielding 5 unacceptable 5
( )1
committees. If Bill and Karl are not on the committee, there are = 21 ways for 7
the 5 members to be chosen, but again if Alice and Jane were to be on the committee,5
( )
there would be = 10 ways to choose the other three members, yielding 10 more 5
unacceptable committees. So, we obtain (35 − 5) + (21 − 10) = 41 ways the committee 3
can be chosen.