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HMMT 二月 2004 · 代数 · 第 4 题

HMMT February 2004 — Algebra — Problem 4

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. Evaluate the sum
    1 1 1 1
    √ √ √ √
      • · · · + .
        2 b 1 c + 1 2 b 2 c + 1 2 b 3 c + 1 2 b 100 c + 1 − 1
解析

英文解析

  1. Evaluate the sum
    1 1 1 1
    √ √ √ √
      • · · · + .
        2 b 1 c + 1 2 b 2 c + 1 2 b 3 c + 1 2 b 100 c + 1
        Solution: 190 / 21
        The first three terms all equal 1 / 3, then the next five all equal 1 / 5; more generally,
        ⌊ ⌋ ⌊ ⌋


        2 2
        for each a = 1 , 2 , . . . , 9, the terms 1 / (2 a + 1) to 1 / (2 a + 2 a + 1) all equal
        1 / (2 a + 1), and there are 2 a + 1 such terms. Thus our terms can be arranged into
        ⌊ ⌋

        9 groups, each with sum 1, and only the last term 1 / (2 100 + 1) remains, so theanswer is 9 + 1 / 21 = 190 / 21.
        − 1