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HMMT 二月 2003 · 团队赛 · 第 6 题

HMMT February 2003 — Team Round — Problem 6

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [40] Prove that any 2-configuration containing e elements is m -separable for some

    1 1
    m ≤ + 2 e + .
    2 4
    A cell of a 2-configuration of a set A is a nonempty subset C of A such thati. for any two distinct elements a, b of C , there exists a sequence c , c , . . . , c of elements
    0 1 nof A with c = a, c = b , and such that { c , c } , { c , c } , . . . , { c , c } are all elements
    0 n 0 1 1 2 n − 1 nof the 2-configuration, andii. if a is an element of C and b is an element of A but not of C , there does NOTexist a sequence c , c , . . . , c of elements of A with c = a, c = b , and such that
    0 1 n 0 n
    { c , c } , { c , c } , . . . , { c , c } are all elements of the 2-configuration.
    0 1 1 2 n − 1 n
    Also, we define a 2-configuration of A to be barren if there is no subset { a , a , . . . , a } of A ,
    0 1 nwith n ≥ 2, such that { a , a } , { a , a } , . . . , { a , a } and { a , a } are all elements of the
    0 1 1 2 n − 1 n n 0
    2-configuration.
解析

英文解析

  1. Prove that any 2-configuration containing e elements is m -separable for some m ≤

    1 1 + 2 e + .
    2 4
    Solution: Suppose m is the minimum integer for which the given configuration C onset A is m -separable, and fix a corresponding labeling of the elements of A . Let A bethe set of all elements with the label i . Then, for any i, j with 1 ≤ i < j ≤ m , thereimust exist a ∈ A , a ∈ A with { a , a } ∈ C , since otherwise the elements of A couldi i j j i j jhave been reassigned the label i , decreasing the number of distinct labels necessary and
    ( )
    thus contradicting the minimality of m . We thus get at least different elements ofm
    ( )2
    1 1 m
    C . Therefore, e ≥ = m ( m − 1) / 2 = [( m − ) − ] / 2, and solving for m gives the 2
    2 2 4
    desired result.
    A cell of a 2-configuration of a set A is a nonempty subset C of A such that 4
    i. for any two distinct elements a, b of C , there exists a sequence c , c , . . . , c of elements
    0 1 nof A with c = a, c = b , and such that { c , c } , { c , c } , . . . , { c , c } are all elements
    0 n 0 1 1 2 n − 1 nof the 2-configuration, andii. if a is an element of C and b is an element of A but not of C , there does NOTexist a sequence c , c , . . . , c of elements of A with c = a, c = b , and such that
    0 1 n 0 n
    { c , c } , { c , c } , . . . , { c , c } are all elements of the 2-configuration.
    0 1 1 2 n − 1 n
    Also, we define a 2-configuration of A to be barren if there is no subset { a , a , . . . , a } of A ,
    0 1 nwith n ≥ 2, such that { a , a } , { a , a } , . . . , { a , a } and { a , a } are all elements of the
    0 1 1 2 n − 1 n n 0
    2-configuration.