HMMT 二月 2003 · 团队赛 · 第 6 题
HMMT February 2003 — Team Round — Problem 6
题目详情
英文原题
- [40] Prove that any 2-configuration containing e elements is m -separable for some
√
1 1
m ≤ + 2 e + .
2 4
A cell of a 2-configuration of a set A is a nonempty subset C of A such thati. for any two distinct elements a, b of C , there exists a sequence c , c , . . . , c of elements
0 1 nof A with c = a, c = b , and such that { c , c } , { c , c } , . . . , { c , c } are all elements
0 n 0 1 1 2 n − 1 nof the 2-configuration, andii. if a is an element of C and b is an element of A but not of C , there does NOTexist a sequence c , c , . . . , c of elements of A with c = a, c = b , and such that
0 1 n 0 n
{ c , c } , { c , c } , . . . , { c , c } are all elements of the 2-configuration.
0 1 1 2 n − 1 n
Also, we define a 2-configuration of A to be barren if there is no subset { a , a , . . . , a } of A ,
0 1 nwith n ≥ 2, such that { a , a } , { a , a } , . . . , { a , a } and { a , a } are all elements of the
0 1 1 2 n − 1 n n 0
2-configuration.
解析
英文解析
- Prove that any 2-configuration containing e elements is m -separable for some m ≤
√
1 1 + 2 e + .
2 4
Solution: Suppose m is the minimum integer for which the given configuration C onset A is m -separable, and fix a corresponding labeling of the elements of A . Let A bethe set of all elements with the label i . Then, for any i, j with 1 ≤ i < j ≤ m , thereimust exist a ∈ A , a ∈ A with { a , a } ∈ C , since otherwise the elements of A couldi i j j i j jhave been reassigned the label i , decreasing the number of distinct labels necessary and
( )
thus contradicting the minimality of m . We thus get at least different elements ofm
( )2
1 1 m
C . Therefore, e ≥ = m ( m − 1) / 2 = [( m − ) − ] / 2, and solving for m gives the 2
2 2 4
desired result.
A cell of a 2-configuration of a set A is a nonempty subset C of A such that 4
i. for any two distinct elements a, b of C , there exists a sequence c , c , . . . , c of elements
0 1 nof A with c = a, c = b , and such that { c , c } , { c , c } , . . . , { c , c } are all elements
0 n 0 1 1 2 n − 1 nof the 2-configuration, andii. if a is an element of C and b is an element of A but not of C , there does NOTexist a sequence c , c , . . . , c of elements of A with c = a, c = b , and such that
0 1 n 0 n
{ c , c } , { c , c } , . . . , { c , c } are all elements of the 2-configuration.
0 1 1 2 n − 1 n
Also, we define a 2-configuration of A to be barren if there is no subset { a , a , . . . , a } of A ,
0 1 nwith n ≥ 2, such that { a , a } , { a , a } , . . . , { a , a } and { a , a } are all elements of the
0 1 1 2 n − 1 n n 0
2-configuration.