HMMT 二月 2003 · CALC 赛 · 第 8 题
HMMT February 2003 — CALC Round — Problem 8
题目详情
英文原题
- A right circular cone with a height of 12 inches and a base radius of 3 inches is filledwith water and held with its vertex pointing downward. Water flows out through ahole at the vertex at a rate in cubic inches per second numerically equal to the heightof the water in the cone. (For example, when the height of the water in the cone is 4
inches, water flows out at a rate of 4 cubic inches per second.) Determine how manyseconds it will take for all of the water to flow out of the cone.
解析
英文解析
- A right circular cone with a height of 12 inches and a base radius of 3 inches is filledwith water and held with its vertex pointing downward. Water flows out through ahole at the vertex at a rate in cubic inches per second numerically equal to the heightof the water in the cone. (For example, when the height of the water in the cone is 4
inches, water flows out at a rate of 4 cubic inches per second.) Determine how manyseconds it will take for all of the water to flow out of the cone.
Solution: 9 π/ 2
When the water in the cone is h inches high, it forms a cone similar to the original, sothat its base has radius h/ 4 and its volume is hence πh / 48. The given condition then 3
states that
( )
3 2
d πh πh dh dh 32 = − h ⇒ · = − h ⇒ 2 h · = − .
dt 48 16 dt dt π
Integrating with respect to t , we get that h = − 32 t/π + C ; setting t = 0, h = 12, we 2
get C = 144. The cone empties when h = 0, so 0 = − 32 t/π + 144 ⇒ t = 9 π/ 2. 2