HMMT 二月 2003 · CALC 赛 · 第 10 题
HMMT February 2003 — CALC Round — Problem 10
题目详情
英文原题
- Evaluate
∫
∞2
1 − xdx.
−∞ 1 + x 4 1
解析
英文解析
- Evaluate
∫
∞2
1 − xdx.
1 + x 4 −∞
Solution: 0
∫
∞
Let S = 1 / ( x + 1) dx ; note that the integral converges absolutely. Substituting 4
x = 1 /u , so that dx = − 1 /u du , we have 20
∫ ∫ ∫
∞ 0 02
1 1 du − u
S = dx = = du
4 − 4 2 4
1 + x 1 + u − u u + 1
0 ∞ ∞
∫ ∫
2 2
∞ ∞
u x = du = dx
4 4
1 + u 1 + x
0 0
(the manipulations are justified by absolute convergence), from which we see that
∫
∞
2 4
(1 − x ) / (1 + x ) dx = 0. Since the integrand is an even function, it follows that the integral from −∞ to ∞ is zero as well.0 3