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HMMT 二月 2003 · 代数 · 第 9 题

HMMT February 2003 — Algebra — Problem 9

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. For how many integers n , for 1 ≤ n ≤ 1000, is the number even?
    2 n
解析

英文解析

  1. For how many integers n , for 1 ≤ n ≤ 1000, is the number even?
    2 n
    Solution: 990
    ( )
    2 n
    In fact, the expression is always even, and it is not a multiple of four if and onlynif n is a power of 2, and there are 10 powers of 2 between 1 and 1000.
    Let f ( N ) denote the number of factors of 2 in N . Thus,
    ⌊ ⌋ ⌊ ⌋ ⌊ ⌋ ⌊ ⌋


    n n n nf ( n !) = + + + · · · = .
    2 4 8 2 kk =1
    Also, it is clear that f ( ab ) = f ( a ) + f ( b ) and f ( ) = f ( a ) − f ( b ) for integers a, b . Nowabm m +1
    for any positive integer n , let m be the integer such that 2 ≤ n < 2 . Then
    (( )) ( ) ( )
    ⌊ ⌋ ⌊ ⌋
    ∞ ∞
    ∑ ∑
    2 n (2 n )! 2 n nf = f = − 2
    k kn n ! n ! 2 2
    k =1 k =1
    ( )
    ⌊ ⌋ ⌊ ⌋
    ∞ ∞
    ∑ ∑
    n n = − 2
    k − 1 k
    2 2
    k =1 k =1
    ( )
    ⌊ ⌋


    = b n c −nkk =12
    ( )
    ⌊ ⌋
    ∑mn = n −
    2 kk =1
    ( )
    ∑mn
    ≥ n −
    2 kk =1
    ( )
    2 − 1 nm = n − n = ≥ 1 .
    m m
    2 2
    ( )
    2 nm
    Both equalities hold when n = 2 , and otherwise, f ( ) > 1. n