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HMMT 二月 2002 · 冲刺赛 · 第 54 题

HMMT February 2002 — Guts Round — Problem 54

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [10] How many pairs of integers ( a, b ), with 1 ≤ a ≤ b ≤ 60, have the property that bis divisible by a and b + 1 is divisible by a + 1?
解析

英文解析

  1. How many pairs of integers ( a, b ), with 1 ≤ a ≤ b ≤ 60, have the property that b isdivisible by a and b + 1 is divisible by a + 1?
    Solution: The divisibility condition is equivalent to b − a being divisible by both aand a + 1, or, equivalently (since these are relatively prime), by a ( a + 1). Any b satisfyingthe condition is automatically ≥ a , so it suffices to count the number of values b − a ∈
    { 1 − a, 2 − a, . . . , 60 − a } that are divisible by a ( a + 1) and sum over all a . The numberof such values will be precisely 60 / [ a ( a + 1)] whenever this quantity is an integer, whichfortunately happens for every a ≤ 5; we count:
    a = 1 gives 30 values of b ;
    a = 2 gives 10 values of b ;13
    a = 3 gives 5 values of b ;
    a = 4 gives 3 values of b ;
    a = 5 gives 2 values of b ;
    a = 6 gives 2 values ( b = 6 or 48);
    any a ≥ 7 gives only one value, namely b = a , since b > a implies b ≥ a + a ( a + 1) > 60.
    Adding these up, we get a total of 106 pairs.