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HMMT 二月 2002 · 代数 · 第 1 题

HMMT February 2002 — Algebra — Problem 1

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. Nine nonnegative numbers have average 10. What is the greatest possible value for theirmedian?
解析

英文解析

  1. Nine nonnegative numbers have average 10. What is the greatest possible value fortheir median?
    Solution: 18 If the median is m , then the five highest numbers are all at least m , sothe sum of all the numbers is at least 5 m . Thus 90 ≥ 5 m ⇒ m ≤ 18. Conversely, we canachieve m = 18 by taking four 0’s and five 18’s.