HMMT 二月 2000 · POW 赛 · 第 1 题
HMMT February 2000 — POW Round — Problem 1
题目详情
英文原题
- A derangemen t of a string of distin t elemen ts is a rearrangemen t of the string suchthat no elemen t app ears in its original p osition. F or example, BCA is a derangemen t of
ABC. D represen ts the number of derangemen ts of an y string omp osed of n distin tnelemen ts. D = 1 and D = 2.
2 3
(a) What are D and D ?
4 5
(b) Ho w man y derangmen ts are there of the string ABCDEF G?
( ) Find a re ursiv e relationship for D in terms of the previous t w o terms ( D andn n 1
D ).
n 2
(d) Find a re ursiv e relationship for D in terms of only the previous term, D .
n n 1
解析
英文解析
- (a) D = 9 ; D = 44
4 5
(b) This is D = 1854
( ) D = ( n 1)( D + D )7
n n 1 n 2
(d) D = n D + ( 1)nn n 1