HMMT 二月 2000 · ORAL 赛 · 第 1 题
HMMT February 2000 — ORAL Round — Problem 1
题目详情
- [25] Find all integer solutions to m = n + 1. 10 9 8 7 6
解析
- The equation involves only even powers, so we may assume m, n are positive (negative 6 6 6 3 6 solutions may be generated by switching signs). n ≤ n + 1 ≤ n + 2 n + 1, so n + 1 lies between two squares, with strict inequality unless n = 0. So the only solutions are m = ± 1 , n = 0. 6 4 3 2