HMMT 二月 2000 · 几何 · 第 3 题
HMMT February 2000 — Geometry — Problem 3
题目详情
- Find P B , giv en that P A = 15 ; P C = 20 ; P D = 7, and AB C D is a square. A B C C C C ##### P aaaaa D C
解析
- Let s b e the side length of AB C D . Sin e AB C D is a square, w e an write 2 s = 2 2 2 2 ( P A ) + ( P C ) = ( P B ) + ( P C ) . So, w e an substitute in for P A , P C , and P D to get that P B = 24 .