HMMT 二月 2000 · GEN 赛 · 第 7 题

求 $\lfloor\sqrt{19992000}\rfloor$。
$4471^{2}=19989841 < 19992000 < 4472^{2}=19998784$，故 $\lfloor\sqrt{19992000}\rfloor = \boxed{4471}$。

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英文解析

Find $\lfloor \sqrt{19992000} \rfloor$.
$4471^{2} = 19989841$ and $4472^{2} = 19998784$.
Since $19989841 < 19992000 < 19998784$, we have $\lfloor \sqrt{19992000} \rfloor = 4471$.
$\boxed{4471}$.