返回题库

HMMT 二月 1998 · CALC 赛 · 第 1 题

HMMT February 1998 — CALC Round — Problem 1

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

Question One . [3 points]
Farmer Tim is lost in the densely-forested Cartesian plane. Startingfrom the origin he walks a sinusoidal path in search of home; that is, after t minutes he is at position ( t , sin t ) .
Five minutes after he sets out, Alex enters the forest at the originand sets out in search of Tim. He walks in such a way that after hehas been in the forest for m minutes, his position is ( m , cos t ) .
What is the greatest distance between Alex and Farmer Tim whilethey are walking in these paths?

解析

英文解析

  1. Problem: Farmer Tim is lost in the densely-forested Cartesian plane. Starting from the origin he walksa sinusoidal path in search of home; that is, after t minutes he is at position ( t, sin t ).
    Five minutes after he sets out, Alex enters the forest at the origin and sets out in search of Tim. Hewalks in such a way that after he has been in the forest for m minutes, his position is ( m, cos t ).
    What is the greatest distance between Alex and Farmer Tim while they are walking in these paths?
    Solution: At arbitrary time t , Farmer Tim is at position ( t, sin t ) and Alex is at position ( t − 5 , cos t ).

    Hence at time t , the distance, d , between Tim and Alex is d = (sin t − cos t ) + 25. To find the maximum 2
    value of d , we solve for t such that = 0.dddt
    (sin t − cos t )(cos t +sin t )
    dd dd 2 2
    2 2

    = . Then = 0 ⇒ sin t − cos t = 0 ⇒ sin t = cos t . Equality happens if t isdt dt
    (sin t − cos t ) +252
    any constant multiple of .π
    Notice that to maximize d , we need to maximize (sin t − cos t ) . This is achieved when cos t = − sin t .24
    Because we determined earlier that t is a constant multiple of , then with this new condition, we see thatπ
    3 π4
    t must be a constant multiple of .
    √4
    Then (sin t − cos t ) = 2 ⇒ d = 29 .2