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HMMT 二月 1998 · 代数 · 第 9 题

HMMT February 1998 — Algebra — Problem 9

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. Suppose f ( x ) is a rational function such that 3 f ( ) + = x for x ≠ 0 .
    Find f ( − 2 . )xx
解析

英文解析

  1. Problem: Suppose f ( x ) is a rational function such that 3 f ( ) + = x for x 6 = 0. Find f ( − 2).
    x x − 1
    Solution: Let x = . Then − 12
    2 f ( )
    3 f ( − 2) + =21 − 1 − 1 124
    ⇒ 3 f ( − 2) − 4 f ( ) = (1)
    2 4
    Let x = − 2. Then − 1 2 f ( − 2)
    3 f ( ) + = 4
    2 − 2 − 1
    ⇒ 3 f ( ) − f ( − 2) = 4 (2)
    Solving this system of equations { (1) , (2) } for f ( − 2) yields f ( − 2) = .672
    20