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HMMT 二月 1998 · ADV 赛 · 第 7 题

HMMT February 1998 — ADV Round — Problem 7

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. The Houson Association of Mathematics Educators decides to hold a grand forum onmathematics education and invites a number of politicians from around the United
    States to participate. Around lunch time the politicians decide to play a game. In thisgame, players can score 19 points for pegging the coordinator of the gathering with aspit ball, 9 points for downing an entire cup of the forum’s interpretation of coffee, or
    8 points for quoting more than three consecutive words from the speech Senator
    Bobbo delivered before lunch. What is the product of the two greatest scores that aplayer cannot score in this game?
解析

英文解析

  1. The Houson Association of Mathematics Educators decides to hold a grand forum on mathematicseducation and invites a number of politicians from the United States to participate. Around lunchtime the politicians decide to play a game. In this game, players can score 19 points for peggingthe coordinator of the gathering with a spit ball, 9 points for downing an entire cup of the forum’sinterpretation of coffee, or 8 points for quoting more than three consecutive words from the speech
    Senator Bobbo delivered before lunch. What is the product of the two greatest scores that a playercannot score in this game?
    Answer: 1209 . Attainable scores are positive integers that can be written in the form 8 a + 9 b + 19 c ,
    where a , b , and c are nonnegative integers. Consider attainable number of points modulo 8.
    Scores that are 0 (mod 8) can be obtained with 8 a for positive a .
    Scores that are 1 (mod 8) greater than or equal to 9 can be obtained with 9 + 8 a for nonnegative a .
    Scores that are 2 (mod 8) greater than or equal to 18 can be obtained with 9 · 2 + 8 a .
    Scores that are 3 (mod 8) greater than or equal to 19 can be obtained with 19 + 8 a .
    Scores that are 4 (mod 8) greater than or equal to 19 + 9 = 28 can be obtained with 19 + 9 + 8 a .
    Scores that are 5 (mod 8) greater than or equal to 19 + 9 · 2 = 37 can be obtained with 19 + 9 · 2 + 8 a .
    Scores that are 6 (mod 8) greater than or equal to 19 · 2 = 38 can be obtained with 19 · 2 + 8 a .
    Scores that are 7 (mod 8) greater than or equal to 19 · 2 + 9 = 47 can be obtained with 19 · 2 + 9 + 8 a .
    So the largest two unachievable values are 39 and 31. Multiplying them gives 1209. 2