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AIME 2008 I · 第 5 题

AIME 2008 I — Problem 5

专题
Contest Math
难度
L4
来源
AIME

题目详情

Problem

A right circular cone has base radius rr and height hh. The cone lies on its side on a flat table. As the cone rolls on the surface of the table without slipping, the point where the cone's base meets the table traces a circular arc centered at the point where the vertex touches the table. The cone first returns to its original position on the table after making 1717 complete rotations. The value of h/rh/r can be written in the form mnm\sqrt {n}, where mm and nn are positive integers and nn is not divisible by the square of any prime. Find m+nm + n.

解析

Solution

The path is a circle with radius equal to the slant height of the cone, which is r2+h2\sqrt {r^{2} + h^{2}}. Thus, the length of the path is 2πr2+h22\pi\sqrt {r^{2} + h^{2}}.

Also, the length of the path is 17 times the circumference of the base, which is 34rπ34r\pi. Setting these equal gives r2+h2=17r\sqrt {r^{2} + h^{2}} = 17r, or h2=288r2h^{2} = 288r^{2}. Thus, h2r2=288\dfrac{h^{2}}{r^{2}} = 288, and hr=122\dfrac{h}{r} = 12\sqrt {2}, giving an answer of 12+2=01412 + 2 = \boxed{014}.