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AIME 2000 I · 第 3 题

AIME 2000 I — Problem 3

专题
Contest Math
难度
L4
来源
AIME

题目详情

Problem

In the expansion of (ax+b)2000,(ax + b)^{2000}, where aa and bb are relatively prime positive integers, the coefficients of x2x^{2} and x3x^{3} are equal. Find a+ba + b.

解析

Solution

Using the binomial theorem, (20001998)b1998a2=(20001997)b1997a3b=666a\binom{2000}{1998} b^{1998}a^2 = \binom{2000}{1997}b^{1997}a^3 \Longrightarrow b=666a.

Since aa and bb are positive relatively prime integers, a=1a=1 and b=666b=666, and a+b=667a+b=\boxed{667}.