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AIME 1995 · 第 11 题

AIME 1995 — Problem 11

专题
Contest Math
难度
L4
来源
AIME

题目详情

Problem

A right rectangular prism PP_{} (i.e., a rectangular parallelpiped) has sides of integral length a,b,c,a, b, c, with abc.a\le b\le c. A plane parallel to one of the faces of PP_{} cuts PP_{} into two prisms, one of which is similar to P,P_{}, and both of which have nonzero volume. Given that b=1995,b=1995, for how many ordered triples (a,b,c)(a, b, c) does such a plane exist?

解析

Solution

Let PP' be the prism similar to PP, and let the sides of PP' be of length x,y,zx,y,z, such that xyzx \le y \le z. Then

xa=yb=zc<1.\frac{x}{a} = \frac{y}{b} = \frac zc < 1. Note that if the ratio of similarity was equal to 11, we would have a prism with zero volume. As one face of PP' is a face of PP, it follows that PP and PP' share at least two side lengths in common. Since x<a,y<b,z<cx < a, y < b, z < c, it follows that the only possibility is y=a,z=b=1995y=a,z=b=1995. Then,

xa=a1995=1995cac=19952=325272192.\frac{x}{a} = \frac{a}{1995} = \frac{1995}{c} \Longrightarrow ac = 1995^2 = 3^25^27^219^2. The number of factors of 3252721923^25^27^219^2 is (2+1)(2+1)(2+1)(2+1)=81(2+1)(2+1)(2+1)(2+1) = 81. Only in 812=40\left\lfloor \frac {81}2 \right\rfloor = 40 of these cases is a<ca < c (for a=ca=c, we end with a prism of zero volume). We can easily verify that these will yield nondegenerate prisms, so the answer is 040\boxed{040}.