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AIME 1994 · 第 14 题

AIME 1994 — Problem 14

专题
Contest Math
难度
L4
来源
AIME

题目详情

Problem

A beam of light strikes BC\overline{BC}\, at point CC\, with angle of incidence α=19.94\alpha=19.94^\circ\, and reflects with an equal angle of reflection as shown. The light beam continues its path, reflecting off line segments AB\overline{AB}\, and BC\overline{BC}\, according to the rule: angle of incidence equals angle of reflection. Given that β=α/10=1.994\beta=\alpha/10=1.994^\circ\, and AB=BC,AB=BC,\, determine the number of times the light beam will bounce off the two line segments. Include the first reflection at CC\, in your count.

AIME diagram

解析

Solution

At each point of reflection, we pretend instead that the light continues to travel straight.

AIME diagram

Note that after kk reflections (excluding the first one at CC) the extended line will form an angle kβk \beta at point BB. For the kkth reflection to be just inside or at point BB, we must have kβ1802αk1802αβ=70.27k\beta \le 180 - 2\alpha \Longrightarrow k \le \frac{180 - 2\alpha}{\beta} = 70.27. Thus, our answer is, including the first intersection, 1802αβ+1=071\left\lfloor \frac{180 - 2\alpha}{\beta} \right\rfloor + 1 = \boxed{071}.